Linux sed：将整行替换为空格开头的文本
直接看代码：
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[root@node1 ~]# cat /etc/keepalived/keepalived.conf | grep priority priority 100 [root@node1 ~]# [root@node1 ~]# sed -i "/priority/c priority 50" /etc/keepalived/keepalived.conf [root@node1 ~]# [root@node1 ~]# cat /etc/keepalived/keepalived.conf | grep priority priority 50 [root@node1 ~]# [root@node1 ~]# sed -i "/priority/c' priority 50'" /etc/keepalived/keepalived.conf [root@node1 ~]# [root@node1 ~]# cat /etc/keepalived/keepalived.conf | grep priority ' priority 50' [root@node1 ~]# [root@node1 ~]# sed -i "/priority/c\ priority 50" /etc/keepalived/keepalived.conf [root@node1 ~]# [root@node1 ~]# cat /etc/keepalived/keepalived.conf | grep priority priority 50 [root@node1 ~]# |
在通过【sed】执行替换的时候，如果替换的目标字符串有空格，需要用【\】转义。
